0=3w^2+4w-64

Solution for 0=3w^2+4w-64 equation:

0=3w^2+4w-64

We move all terms to the left:

0-(3w^2+4w-64)=0

We add all the numbers together, and all the variables

-(3w^2+4w-64)=0

We get rid of parentheses

-3w^2-4w+64=0

a = -3; b = -4; c = +64;
Δ = b2-4ac
Δ = -42-4·(-3)·64
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*-3}=\frac{-24}{-6}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*-3}=\frac{32}{-6}
=-5+1/3
$